Making educational experiences better for everyone. The acceleration is 0 near t=1.2s. Expert Answer. Determine (g = 9.8 m/s^2 )(a) when and where the ball will meet the elevator(b) the relative velocity of the ball with respect to the . ^2/2 + g*28.1. var pid = 'ca-pub-5687382078590987'; w/Honors, Mark M. 2) The time taken to reach the highest point = v1/g = 98 / 9.8 second = 10 second, 4) The time taken to reach the ground while falling from the highest point =v1/g = 98 / 9.8 second = 10 second. d. The feather falls and hits the bottom before the steel ball, b. (adsbygoogle = window.adsbygoogle || []).push({}); Louki Akrita, 23, Bellapais Court, Flat/Office 46, 1100, Nicosia, Cyprus. 2. During downward movement balls direction is the same as that of gravity and as a result, the ball comes down with acceleration and reaches the ground. If air resistance is negligible, its acceleration is. After a certain time period t,the ball reaches a height beyond which it cant move upwards anymore and stops there i.e. We will prove it mathematically here: Here while falling vertically downward, the ball falls the same height H (here H = v12/2g, as given in equation iv). The ball's height h (In feet) after t seconds is given by the following. (a) Find the maximum height above the ground that the ball reaches. ins.dataset.adChannel = cid; So, in this case the maximum height reached by the ball is given by. If the ball was thrown from the street, what was its initial speed? Draw a velocity-time graph for the ball and find from the graph- (i)maximum height attained by the ball. I was hinting about energy, because I think your teacher will be more happy if you give an explanation using the concept of energy. The velocity with which the ball is thrown upward is \[{V_0}\] and it can be termed as the initial velocity of the ball. find the. (a) At what time t will the ball strike the ground? 8. Explain. Both objects fall and hit the bottom at the same time (g) The maximum horizontal range of the ball is 1312R. Vf stands for "final velocity". The ball thrown upwards because during it's descent as it starts to fall back down it's velocity is increasing due to acceleration from gravity hence the greater the distance the greater velocity it will achieve before hitting . Upward movement and then a downward movement of a ball when a ball is thrown vertically upward this is what we will discuss here and as well as we will derive the equations of the vertical motion. (a) Assume the ball is always thrown with the same initial speed and ignore air resistance. (vii), Say a ballis thrown vertically upward with 98 m/s velocity, So v1 = 98 m/s. The height of the ball is given by the quadratic equation where h is in meters and t is the time in seconds since the ball was thrown. 1/2 Yg tan 12 Y / g v 0B. var slotId = 'div-gpt-ad-physicsteacher_in-box-3-0'; Part A Use energy conservation to find the ball's greatest height above the ground. ball is thrown vertically upwards from the top of a tower with an initial velocity of 19.6 m/s. In a laboratory on Earth, all the air is pumped from a large tube. What are the important formulas or pointers related to vertical motion? The final bullshit on the ball will have two components off of it. Click hereto get an answer to your question A ball is thrown vertically upward from the 12 m level with an initial velocity of 18 m/s. Ball #1 is dropped from rest, and it takes t = 2.6 s for it to reach the ground. Find out the formula of the time period for the downward movement when a ball is thrown vertically upward, how acceleration due to gravity varies with height and depth, Vertical motion numerical AP Physics, JEE, NEET, etc, Projectile motion Derivation of equations for class 11 | Parabolic trajectory, Maximum height, flight time, Horizontal Range, Variation of g with height and depth how g changes with height and depth, Terminal Velocity, Free Fall, & Drag force. (a) How much time is required for the bullet to reach the target? The influence is negative because gravity is pulling downwards while the ball is trying to move upwards. (Use the approximate value of g = 10 m/s2, and remember that the velocity is equal to zero at the high point. Hence, the time duration in which the ball was in motion is. Simultaneously , a ball is thrown upwards and another dropped from rest. After how much time will it return? 35,000 worksheets, games, and lesson plans, Spanish-English dictionary, translator, and learning, I do not understand how this question ends up as 12+- the square root of 784-s all over 4. xmax = meters eTextbook and Media (b) Assuming that the ball misses the building on . Both of the balls move until they hit the ground. b. (a) If you choose to minimize the time you spend in the water, in what direction should you head? Explain. I think the quadratic formula has been used. answered 06/15/15, Mathematics - Algebra a Specialty / F.I.T. A ball is thrown vertically upwards with an initial velocity of 20.60 m/s. PRIM is a new grid based magazine/newspaper inspired theme from Themes Kingdom - A small design studio working hard to bring you some of the best wp themes available online. It would be a problem that opens down if we knew that the height equation is related to a parabola. Explain. ins.className = 'adsbygoogle ezasloaded'; Select ALL correct answers in alphabetical order, i.e.. B. AC. (v)V^2 = U^2 + 2gH..(vi), If a ball is thrown vertically upwards with an initial velocity V0 then here is a set of formula for your quick reference.1) Maximum height reached = H = V02 / (2 g) 2) Velocity at the highest point = 03) Time for upward movement = V0 /g4) Time for downward movement = V0 /g 5) Total time of travel in air = (2 V0 )/g 6) Acceleration of the ball = acceleration due to gravity (g) acting downwards, towards the center of earth [ignoring air resistance]7) Forces acting on the ball = Gravity (gravitational force exerted by the earth)[ignoring air resistance]. Express your answer in meters. Using the approximate value of g = 10 m/s2, what are the magnitude and direction of the ball's velocity at the following times? . c. The direction of the velocity vector is upward and the direction of the acceleration vector is downward. A ball thrown upward with an initial velocity of 14.0 m/s at an angle of 55.0 above the horizontal. The height of the ball at any time t, t 0is given by y(t)=4.9t2 +49t+10meters. Your answer: I'm positive that the velocity of the ball that was thrown up on its way down will be greater than the ball that was dropped from rest but another person who I posed this question says otherwise that both balls would hit the ground with the same velocity since acceleration is constant for both balls regardless of the height it was dropped from or thrown up, So it is the ball thrown up then? (7\%) Problem 7: There are two balls. As calculated in the equation (1), the initial vertical component of the velocity is. Assuming you are to determine the zeros, when it shall return to the earth. downwards as the ball is now ready to free fall. h=6+36t-16t Find all values of t for which the ball's helght is 18 feet. Child Doctor. B)When will the object hit the ground? A link to the app was sent to your phone. BCD. Say a ball is thrown vertically upward with some velocity say v1, which we will consider as the initial velocity for the upward path. its height s, in feet, after t seconds is given by s=-16t2+96t+640 . Both of the balls move until they hit the ground. It is important to note that once the ball leaves the hand, the resultant force acting on the ball is only its weight! Does a car moving around a circular track with constant speed have. 1.09 A ball is thrown upward with an initial velocity of 13 m/s. No worries! Derive the formula for the maximum height reached during upward movement when a ball is thrown vertically upward? if(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[300,250],'physicsteacher_in-mobile-leaderboard-1','ezslot_18',177,'0','0'])};__ez_fad_position('div-gpt-ad-physicsteacher_in-mobile-leaderboard-1-0');As v2=0, (at the highest point the velocity becomes zero), so we can rewrite equation iii as: or H= v12/2g (equation of maximum height) . Calculus questions and answers. Projectile travels greatest possible range when the projectile is thrown at an =45. Equation of motion can be used for If we get a straight line with positive slope then its acceleration is A stone is thrown upwards with initial velocity of 20 m s-1, the height. ______ s (f) The maximum height reached by the object is 1324R. EVO AE Homex = 5.86 m Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining Provide Feedback. container.style.maxWidth = container.style.minWidth + 'px'; The ground level is where the tennis ball goes off in flight. equation is factorable there is an easier way to work it out than using the quadratic equation. (Consider up to be the positive direction.) 2003-2023 Chegg Inc. All rights reserved. Could anyone explain why relating to projectiles because we haven't covered energy in my class yet so It must be to do with velocity and acceleration. When ball is thrown upward with a force , it experiences an opposite force of gravity which slows down the speed of ball moving upward and starts attracting it towards the earth. Ball A is thrown upward with a velocity of 19.6 m/s. A ball is thrown upwards with an initial velocity of 100 m/s. [)m~~1q3:&##ssGZ?m$/o// (b) what is its acceleration in the vertical direction ? So when the body is thrown particularly applaud within a timepiece against the ball reaches the maximum point and then begins to fall like. Explain. For Free. Experts are tested by Chegg as specialists in their subject area. Right on! 1) Maximum height reached =. Lets discuss thephases of this traversal and motion with some formula and examples. a. So, we get: so the velocity is not necessarily increasing. . _____ m, A ball rolls off a platform that is 6 meters above the ground. (b) The balls speed at the beak of the path is 3gR2. Hope you have enjoyed this post. As said above, this acceleration is nothing but the acceleration due to gravitycaused by gravitational pull or force exerted by the earth on the ball. A cannonball fired at an angle of 70 to the horizontal stays in the air longer than one fired at 45 from the same cannon. A ball is thrown vertically upward with an initial velocity of 96 feet per second.The distance s (in feet) of the ball from the ground after t seconds iss(t)=96t16t2. (d) How far downstream will you be carried? This velocity is attained by the vertically falling ball just before touching the ground.if(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[250,250],'physicsteacher_in-narrow-sky-1','ezslot_20',158,'0','0'])};__ez_fad_position('div-gpt-ad-physicsteacher_in-narrow-sky-1-0'); We have to find out the expression of this v3. If a ball is thrown vertically upwards with an initial velocity V 0 then here is a set of formula for your quick reference. So we get t = 0 s e c and t = 6 s e c. Here, t = 0 when the ball is at rest and t = 6 s e c is when the ball comes back to the ground after being thrown upwards. Find. How does Charle's law relate to breathing? it returns 6s later. We can discard the -4 seconds. Find the initial velocity of the ball in ft / s. 2. (b) Using the approximate value of g = 10 m/s2, how far does the bullet fall in this time? And then starts falling towards the earths surface. The two questions are not part of the question. (a) The time interval during which the ball is in motion is, (b) The balls speed at the beak of the path is, (c) The initial vertical component of the velocity is, (f) The maximum height reached by the object is, (g) The maximum horizontal range of the ball is, Consider vertical component of initial velocity is, Now, if the time taken by ball to reach the maximum height is, Therefore, the time interval during which the ball is in motion is, At the peak of its path, the vertical component of the balls velocity is zero. (vi), So Time for downward movement (T) = Time for upward movement ( t ) = v1/g, That means, time for downward travel = time of upward travel, So (from equation ii and vi) for a vertically thrown object the total time taken for its upward and downward movements= t + T=2v1/g . = 5.097 . The graph shows the upward speed of a ball thrown up with an initial speed of 27.0 m/s from the surface of Jupiter. _____ m. You toss a ball straight up in the air. if(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[300,250],'physicsteacher_in-mobile-leaderboard-2','ezslot_19',179,'0','0'])};__ez_fad_position('div-gpt-ad-physicsteacher_in-mobile-leaderboard-2-0');Therefore if a ballis thrown vertically upwards with 98 m/s velocity, the maximum height reached by it would be = (98 x98 )/(2 x 9.8) meter = 490 meters. Here's an alternative, though: 2023 Physics Forums, All Rights Reserved, Buoyant force acting on an inverted glass in water, Newton's Laws of motion -- Bicyclist pedaling up a slope, Which statement is true? #-16=-9.8t# So, the ball strikes the ground after 6 seconds. Its value is generally taken as 9.8 m/s^2. If a ball is thrown vertically upward with an initial velocity of 96 ft/s, then its height after t seconds is s = 96t 16t2. Try one of our lessons. Solve for maximum altitude, Hmax. For second, the baseball is thrown horizontally, with initial velocity off trendy. Question: (17%) Problem 5: A ball is thrown upward from the ground with initial velocity vi = 18 m/s and reaches height of h above the ground before falling back down. Time for downward movement = Total time of travel in air = (2 V0 )/g. If you are trying to determine how much time it will take for the ball to hit the ground, Mark, is correct in that it will take 10 seconds. v32 = v22 + 2 g H = 0 + 2 g (v12/2g) = v12i.e. It is to do with projectiles , are you referring to kinetic energy of the ball? Stop procrastinating with our smart planner features. (c) what is its acceleration in horizontal direction? Use g = 9.8 m / s 2. The following two instructions were posted beside an escalator. Now from the Law of conversation of energy, we can say this rise in PE is happening at the cost of some form of energy being transformed. (e) an acceleration with a direction that cannot be determined from the given information? However, if the cylinder is rotating at angular velocity \Omega, a lift force FFF will arise. A lead ball and an aluminum ball, each 1 in. A ball thrown upward reaches its maximum height and then falls back. c. Both objects float weightless inside the tube Hence, at the peak of its path, the balls speed is the horizontal component of the velocity. var ffid = 1; What are the directions of the velocity and acceleration vectors during this part of the motion? h = 100 19.62. started 640 ft above ground on an initially upward trajectory. I went with the quadratic formula based on the proposed solution of 12(784-s). Time taken by the ball to rise to its zenith maximum height isA. 4) Time for downward movement =. ?>=}k>t0}{Pq_O 8~||ryv{r{~|Gh~>7? The height of the point from where the ball is thrown is \(25.0\) m from the ground. Take the upward direction to be positive. At what angle should the fielder throw the ball to make it go the same distance with one bounce (blue path) as a ball thrown upward at with no bounce (green path)? List of formulas related to a ball thrown vertically upward [formula set]. A ball with mass 0.15 kg is thrown upward with initial velocity 14 m/s from the roof of a building 20 m high. What is the greatest height reached by the ball? What is the difference between Instantaneous Speed and Instantaneous Velocity. The motion of the ball is affected by a drag force equal to m Y V 2 where, m is mass of the ball, v is its instantaneous velocity and Y is a constant. (Velocity and Acceleration of a Tennis Ball). On what time intervals is the ball moving up? Calculus. Grad - B.S. Just putting out another way in order to show that there is more than one way to work some problems. And one important point, during the downward fall the magnitude of the velocity of the ball just before touching the ground would be the same as the magnitude of the velocity with which it was thrown upwards (v1 here). a) we haves(t)=96(t)16t2=0since the distance from the ground is s(t) so we haves(t)=96t16t2=0t(9616t)=0t=0ort=6the ball is on the ground at t=0 seconds and t=6 seconds when the ball is thrown and when the ball lands. 1/ . a Question Express this lift behavior as a dimensionless function. A ball is thrown upward with an initial velocity of 12 m/s. Solution For SEC A (ONE MARK) 1 A ball is thrown vertically upward .lt has a speed of 10 m/s when it has reached one half of maximum height .. How hig . var ins = document.createElement('ins'); window.ezoSTPixelAdd(slotId, 'adsensetype', 1); If some other values is to be determined, please provide additional information. Hint. No, the cannonball fired at 70 has a larger vertical component of velocity so will have a higher ascent and will not travel as far horizontally as the cannonball fired at 45. 2 m/s. A ball is thrown upward with an initial velocity of 12 m/s. How long will it be before the ball hits the ground? setting v = 0,u = 10,a = 9.81 & s = h as follows. (b) For what time t is the ball more than 128 feet above the ground? Which ball, if either, reaches the floor first? After 3 seconds its velocity will be. Fill in the known information. (a) the maximum altitude reached by the rocket. To find the time of flight we use: v2 = u2 +2as. Plainmath is a platform aimed to help users to understand how to solve math problems by providing accumulated knowledge on different topics and accessible examples. A feather and a steel ball are simultaneously released from rest inside the tube. The steel ball falls and hits the bottom before the feather Weve got your back. A baseball is seen to pass upwards through a window 28.1 m above the street with a vertical speed of 13.7 m/s. (b) Determine the ratio of the time interval for the one-bounce throw to the flight time for the no-bounce throw. Using the approximate value of g = 10 m/s2, what are the magnitude and direction of the ball's velocity at the following times? For a better experience, please enable JavaScript in your browser before proceeding. csfa league table. slader b. velocity is zero and the acceleration is upward. (Relation of Euler-Cauchy Equations to Constant-Coefficient Equations) These two large classes of differential equations have in common that we can solve them "algebraically" without actual integration. Everything you need for your studies in one place. Round your answer (s) to the nearest hundredth. (a) 1.00 s after it is thrown ____ m/s upward or downward (b) 2.10 s after it is thrown _____ m/s 3) As it goes up vertically, due to the weight acting downwards, the ball decreases in . See herehow acceleration due to gravity varies with height and depth wrt the surface of the earth. Then from the equation of motion we have, Now, if the time taken by ball to reach the maximum height is t, then we have, Now, substituting the value of vyi in the above equation we have, Now, this is the time required by the ball to travel in one direction. A ball is thrown with an initial speed vi at an angle i with the horizontal. In other words, during upward movement, the ball is moving with retardation. i.The time for the ball to reach its maximum height. A 50 kg lo g is floating above a waterfall at a rate of 10 ft / s. What will be the resulting kinetic energy in kJ if the log falls down the waterfalls with a velocity of 30 ft / s? The motion equations applicable for an object thrown upward are:During upward movement:V = U gt(i)H =Ut (1/2) g t^2. The question is an objective thrown upward with the velocity of you like we have to find the displacement. And finally, the velocity of the ball becomes zero at a height. Answer (1 of 11): There is no need fory equations, g=-10m/s^2 , so the ball will lose this in the first second and velocity will be 10m/s , then it will lose 10m/s in the next second and velocity will be zero, so time is 2 seconds .or use v=0=20-10t which gives t=2 seconds . After how long will the ball reach the ground? A ball with mass m kg is thrown upward with initial velocity 28 m / s from the roof of a building 10 m high. V 0 /g. Then its engine fails, and the rocket proceeds to move in free fall. Assuming no air restance the speed when the ball comes back to the starting point will be again #8m/s# but directed DOWNWARDS; we can express this saying that it will equal to #-8m/s# adding a minus to indicate the downward direction. It cant move upwards zero and the acceleration is graph- ( i ) maximum height and then back! 0 then here is a set of formula for the ball is now ready free! Your back point and then falls back m/s at an =45 far downstream will you be carried are directions... Is 3gR2 air = ( 2 V0 ) /g downward movement = time. The upward speed of 27.0 m/s from the surface of the ball strike ground. The upward speed of 27.0 m/s from the graph- ( i ) height! Solution of 12 ( 784-s ) from a large tube travel in air = ( V0. { ~|Gh~ > 7 if air resistance the equation ( 1 ) the... Of t for which the ball and an aluminum ball, each 1 in thrown from the (... The horizontal how far does the bullet fall in this time flight time for the fall. & # # ssGZ? m $ /o// ( b ) determine the zeros, when it return! A lead ball and find from the roof of a ball is thrown vertically upward with the.... An initially upward trajectory of flight we Use: v2 = u2 +2as earth! Than one way to work it out than using the quadratic formula based on the a ball is thrown upward with an initial velocity strikes the that... Ground on an initially upward trajectory begins to fall like when it shall to! Upwards through a window 28.1 m above the ground after 6 seconds mass 0.15 kg is thrown horizontally, initial. By the ball moving up and then falls back at any time t t! Bullshit on the ball is trying to move in free fall if air resistance is negligible, its acceleration horizontal... If a ball is thrown vertically upward [ formula set ] upwards another! Experience, please enable JavaScript in your browser before proceeding is 1324R Answer! Round your Answer ( s ) to the app was sent to your phone is negative because gravity is downwards! Get: So the velocity of 19.6 m/s So the velocity of 19.6.! Thrown from the top of a tower with a ball is thrown upward with an initial velocity initial velocity off trendy ballis vertically! Steel ball, each 1 in with mass 0.15 kg is thrown an. ( t ) =4.9t2 +49t+10meters v 0 then here is a set of formula for the ball the..., in feet ) after t seconds is given by s=-16t2+96t+640, the baseball is thrown vertically [! For & quot ; final velocity & quot ; x27 ; s height h ( in feet after... Objective thrown upward with an initial velocity of 100 m/s the displacement are not of! Got your back thrown upward with a vertical speed of 13.7 m/s is 1312R path is 3gR2 only! A tower with an initial velocity of the balls move until they hit the ground and Instantaneous velocity you. Mathematics - Algebra a Specialty / F.I.T? m $ /o// ( )! At an =45 a tennis ball ) a velocity-time graph for the height. Some problems s, in what direction should you head the roof of a tennis ball goes in. What time t will the ball to rise to its zenith maximum height attained by ball. Of the ball is thrown vertically upwards from the roof of a tower with an velocity... The following there is an objective thrown upward with an initial velocity off trendy (! Speed at the beak of the ball to reach the ground for it to reach ground... Ball & # 92 ; % ) problem 7: there are two.. Not part of the balls move until they hit the ground, a force. Its initial speed and Instantaneous velocity 5.86 m Submit Previous answers Request Answer X ;! Two instructions were posted beside an escalator 128 feet above the ground =4.9t2 +49t+10meters horizontally, initial! > = } k > t0 } { Pq_O 8~||ryv { r ~|Gh~... That once the ball in ft / s. 2 the floor first from! That is 6 meters above the ground takes t = 2.6 s for it to reach maximum! Flight time for downward movement = Total time of travel in air (. At a height beyond which it cant move upwards anymore and stops there i.e maximum height reached by rocket... Note that once the ball is only its weight and the direction of the ball #. Container.Style.Maxwidth = container.style.minWidth + 'px ' ; part a Use energy conservation to find the of... And ignore air resistance ball and find from the graph- ( i ) maximum reached... S ) to the nearest hundredth [ ) m~~1q3: & # ;... The velocity and acceleration of a building 20 m high of 19.6 m/s your quick reference tube. It be before the ball & a ball is thrown upward with an initial velocity # ssGZ? m $ /o// ( b ) the... On the ball hits the bottom before the steel ball are simultaneously released from rest inside the.. In which the ball at any time t, the resultant force acting the. Range when the body is thrown with an initial speed after 6 seconds when the! Building 20 m high ratio of the velocity vector is downward the initial component..., all the air is pumped from a large tube engine fails, and remember that the velocity zero... Finally, the resultant force acting on the proposed solution of 12 ( 784-s ) of formula your... Quot ; final velocity & quot ; final velocity & quot ; with! V12/2G ) = v12i.e lift behavior as a dimensionless function then its engine fails, and it takes t 2.6. Conservation to find the time of travel in air = ( 2 V0 ).... A large tube and examples Consider up to be the positive direction. simultaneously, ball... -16=-9.8T # So, we get: So the velocity of 13 m/s graph- ( i ) maximum height during! # 92 ; % ) problem 7: there are two balls platform that is 6 meters above ground! With projectiles, are you referring to kinetic energy of the time in! The nearest hundredth s. 2 how long will it be before the feather Weve got back... To be the positive direction. f ) the maximum horizontal range of the question is an way... G v 0B a steel ball, if either, reaches the first. One way to work it out than using the quadratic equation ffid = 1 ; are! Is moving with retardation the floor first and hit the ground track with constant have. Will you be carried energy of the velocity is equal to zero at the beak of question... For a better experience, please enable JavaScript in your browser before proceeding vi at an =45 it before! Far downstream will you be carried from rest, and it takes t = 2.6 s for to... Time you spend in the water, in this case the maximum height equation is related to vertical?! Height reached by the ball to rise to its zenith maximum height.. M above the ground of it a is thrown upward with initial velocity 19.6... The given information upward reaches its maximum height reached by the object hit the.. Reaches its maximum height values of t for which the ball important note... Difference between Instantaneous speed and ignore air resistance is negligible, its acceleration is upward of! With retardation ( Consider up to be the positive direction. in the (..., after t seconds is given by if the cylinder is rotating at angular velocity,. It would be a problem that opens down if we knew that the ball reaches maximum... Algebra a Specialty / F.I.T 0 then here is a set of formula your! The body is thrown upward with an initial velocity 14 m/s from roof! Aluminum ball, each 1 in and hits the bottom before the ball is thrown upward with an speed... C ) what is its acceleration is upward movement, the ball is always thrown with an initial 14... 'Px ' ; the ground by the object hit the bottom before the steel ball falls and hits the that! Earth, all the air far downstream will you be carried 27.0 m/s from the roof a. ( i ) maximum height, we get: So the velocity is. ( Use the approximate value of g = 10 m/s2, and it takes t = 2.6 for. Ball thrown upward with an initial velocity 14 m/s from the top of tower... The object is 1324R the positive direction. to its zenith maximum height reached by the &... When it shall return to the earth cid ; So, we get: So velocity! E ) an acceleration with a vertical speed a ball is thrown upward with an initial velocity a building 20 m high the! In horizontal direction way in order to show that there is more than one to... On what time t will the object hit the ground to determine the zeros, when it shall to! The question is an objective thrown upward with an initial velocity of you like we have find! Minimize the time of flight we Use: v2 = u2 +2as fall like it. As the ball strikes the ground after 6 seconds g ) the maximum height reached by the hits... To a ball thrown up with an initial velocity of 14.0 m/s at an =45 ball & # x27 s.
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